Exactly What Does & Suggest?
Exactly what does & suggest by possibility? I am aware that & means ‘and’, but amp has wondering.
Where 3 5 & provides 1
The bits in each place in the 1st quantity (chr) must match bits in each place within the second quantity. Right right Here just the people in red.
One other place either have actually 0 and 0 equals 0 or 1 and 0 equals 0. Nevertheless the final position has 1 and 1 equals 1.
Do you need more explanation – or can you simply instead skip it.
Did you run into this in just one of ACES guages and desired to understand how it worked?
Think about it you really must have counted in binary as a young child
Zero one ten eleven a hundred a hundred and something a hundred and ten a hundred and eleven.
I’d like to explain or even to you.
No No make him stop. I’ll talk, We’ll talk
Ron – i might have understood just what the AND operator implied – a very long time ago – in university.
Therefore utilizing your instance, 3,5 OR gives me personally “6”?
Hey dudes, exactly what does & suggest by opportunity? I am aware that & means ‘and’, but amp has wondering. Many thanks,
While Ron is “technically proper, ” i am let’s assume that you merely desired to understand the following:
& is simply the “full method” of writing the “&” expression.
. Exactly like >: could be the way that is”full of composing “”.
(Hint: the expression is named an “ampersand” or “amp” for short! )
In FS XML syntax, it really is utilized similar to this:
&& is similar as && is equivalent to and
I recently explained this in another post in regards to an ago week.
You did XOR – exclusive OR
The bits are compared by you vertically – in my own examples
The picture is got by you.
A 1 OR 0 is 1 A 0 OR 1 is 1 A 1 OR 1 is 1 A 0 OR 0 is 0
A 1 OR 0 is 1 A 0 OR 1 is 1 A 1 OR 1 is 0
+ (binary operator): adds the past two stack entries – (binary operator): subtracts the final two stack entries * (binary operator): multiplies the very last two stack entries / (binary operator): divides the very last two stack entries percent (binary operator): rest divides the very last two stack entries /-/ (unary operator): reverses indication of final stack entry — (unary operator): decrements last stack entry ++ (unary operator): increments final stack entry
(binary operator): ”” provides 1 if final stack entry is higher than forelast stack entry (binary operator): ” >=; (binary operator): ”=” provides 1 if final stack entry is more than or add up to forelast stack entry <=; (binary operator): ” == (binary operator): offers 1 if both final final stack entries are equal && (binary operator): ”&&” rational AND, if both final stack entries are 1 provides 1 otherwise 0 || (binary operator): logical OR, if a person associated with the final stack entries is 1 outcome is 1 otherwise 0! (unary operator): rational never, toggles last stack entry from 1 to 0 or 0 to at least one? (ternary operator): ”short if-statement”, in the event that last entry is 1, the forelast entry can be used, else the fore-forelast ( or even the other way round. Check it out, notice it)
& (binary operator): ”&” bitwise AND | (binary operator): bitwise OR
(unary operator): bitwise NOT, toggles all bits (binary operator): ” (binary operator): ”” change bits of forelast stack entry by final stack actions off to the right
D: duplicates final stack entry r: swaps last two stack entries s0, s1, s2.: shops stack that is last in storage for later use sp0, sp1, sp2.: (presumably) exactly the same as above l0, l1, l2.: lots value from storage space and places along with stack
(unary operator): provides next smallest integer dnor (unary operator): normalizes degrees (all values are ”wrapped around the group” to 0°-360°) rnor (unary operator): normalizes radians (all values are ”wrapped across the circle” to 0-2p) (NOTE: does not work too dependable) dgrd (unary operator): converts levels to radians (also rddg available? ) pi: places p over the top of stack atg2 (binary operator): gives atan2 in radians (other trigonometric functions? Sin, cos, tg? Other functions? Sqrt, ln? ) maximum (binary operator): provides greater of final two stack entries min (binary operator): provides the smaller of final two stack entries
Other people: if if final stack entry is 1, the rule within the brackets is performed (remember that there is absolutely no AREA between ”if” and ”<” but one after it and at least one SPACE before ”>”) if < . >els if last stack entry is 1, the rule in the brackets is christian mingle number performed, else the rule within the 2nd collection of brackets ( just take also care to where SPACEs are permitted and where perhaps perhaps not) stop makes the execution straight away, final stack entry is employed for further purposes instance difficult to explain, consequently a good example:
30 25 20 10 5 1 0 7 (A: Flaps handle index, quantity) situation
The figures 30 25 20 10 5 1 0 are pressed along the stack, 7 states just just how entries that are much on the basis of the results of (A: Flaps handle index, quantity) ”case” extracts one of several seven figures. If (A: Flaps handle index, number) is 0 – 0, 1-1, 2-5. 6-30.